73·STUDY

Extra exam question E7D13

Subelement E7, PRACTICAL CIRCUITS· Group E7D

E7D13

Which of the following calculates power dissipated by a series linear voltage regulator?

  • A.Input voltage multiplied by input current
  • B.Input voltage divided by output current
  • C.Voltage difference from input to output multiplied by output current (correct answer)
  • D.Output voltage multiplied by output current

WhyPower dissipated by a series linear voltage regulator is calculated as the voltage difference from input to output multiplied by the output current. Power dissipated by a series linear voltage regulator is found by multiplying the voltage difference between its input and output by the output current flowing through it, since that voltage drop times the current passing through the pass transistor is exactly the power being converted to heat in that device, answer C. Input voltage times input current, input voltage divided by output current, and output voltage times output current don't correctly capture what's actually being dissipated specifically in the regulator's own pass element.

Published 2026-08-28 · Last updated 2026-08-28 · Question text is verbatim from the 2024-2028 NCVEC Element 4 pool (public domain); the explanation above is original writing, see our methodology.

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