Extra exam question E9E08

WhyA Wilkinson divider divides power equally between two 50-ohm loads while maintaining 50-ohm input impedance. A Wilkinson divider splits power equally between two 50-ohm loads while still presenting a clean 50-ohm impedance at its input, a common way to feed two identical loads (like a pair of antennas) from a single 50-ohm source without disturbing that source's expected impedance, answer C. It doesn't divide operating frequency, isn't for feeding high-impedance antennas from a low-impedance source, and it isn't a frequency divider for a counter circuit, those aren't what a Wilkinson divider is built to do.