Extra exam question E8A05
Subelement E8, SIGNALS AND EMISSIONS· Group E8A
What is the benefit of making voltage measurements with a true-RMS calculating meter?
- A.An inverse Fourier transform can be used
- B.The signal’s RMS noise factor is also calculated
- C.The calculated RMS value can be converted directly into phasor form
- D.RMS is measured for both sinusoidal and non-sinusoidal signals (correct answer)
WhyThe benefit of a true-RMS calculating meter is that it measures RMS for both sinusoidal and non-sinusoidal signals. A true-RMS calculating meter's real benefit is that it correctly measures RMS value for both sinusoidal and non-sinusoidal (distorted or complex) waveforms, unlike simpler meters that only read accurately on a pure sine wave and assume that shape when calculating RMS, answer D. It doesn't use an inverse Fourier transform, doesn't calculate a separate "RMS noise factor," and doesn't convert directly into phasor form, those aren't what makes a true-RMS meter useful.
Published 2026-08-28 · Last updated 2026-08-28 · Question text is verbatim from the 2024-2028 NCVEC Element 4 pool (public domain); the explanation above is original writing, see our methodology.
Related questions
- E8A01What technique shows that a square wave is made up of a sine wave and its odd harmonics?
- E8A02Which of the following is a type of analog-to-digital conversion?
- E8A03Which of the following describes a signal in the time domain?
- E8A04What is “dither” with respect to analog-to-digital converters?
- E8A06What is the approximate ratio of PEP-to-average power in an unprocessed single-sideband phone signal?